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	<title>Comments on: Speed, distance and time</title>
	<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/</link>
	<description>Mainly for evening and part time Maths students in FE Colleges</description>
	<pubDate>Wed, 10 Mar 2010 03:45:07 +0000</pubDate>
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		<title>by: Hola me llamo rodregez</title>
		<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-7535</link>
		<pubDate>Sun, 28 Feb 2010 12:12:03 +0000</pubDate>
		<guid>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-7535</guid>
					<description>this has helped me so much. i finally underastand english science equations. they kept getting things wrong though but they might be good at science just rubbish at english. very good if learning english, italian, finish, german, austrlien, austrian, american and irish.</description>
		<content:encoded><![CDATA[<p>this has helped me so much. i finally underastand english science equations. they kept getting things wrong though but they might be good at science just rubbish at english. very good if learning english, italian, finish, german, austrlien, austrian, american and irish.
</p>
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		<title>by: hhhjhjhjhjhjhjhj</title>
		<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-7534</link>
		<pubDate>Sun, 28 Feb 2010 12:07:31 +0000</pubDate>
		<guid>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-7534</guid>
					<description>jjjjjjjjjjjjjjjj</description>
		<content:encoded><![CDATA[<p>jjjjjjjjjjjjjjjj
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		<title>by: JenifferOF</title>
		<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-7153</link>
		<pubDate>Sat, 06 Feb 2010 15:14:51 +0000</pubDate>
		<guid>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-7153</guid>
					<description>I will thank you very much for the smashing data about this topic! And you know, that the &lt;a href="http://www.4writers.net" rel="nofollow"&gt;freelance writing &lt;/a&gt; would like to take that stuff at the term papers.</description>
		<content:encoded><![CDATA[<p>I will thank you very much for the smashing data about this topic! And you know, that the <a href="http://www.4writers.net" rel="nofollow">freelance writing </a> would like to take that stuff at the term papers.
</p>
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		<title>by: Anthony</title>
		<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-7121</link>
		<pubDate>Thu, 04 Feb 2010 12:57:06 +0000</pubDate>
		<guid>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-7121</guid>
					<description>This formula is really good just need to know how it works , it troubled me for ages.
so if you want to find the speed you traveled , a boat covers 16.2miles in 1 hour and 25 min.
speed = D/T  
25/60 =0.41666 + ! = 1.41666
16.2 / 1.41666 = 11.435
So around 11.4 knots was the boats speed

So if a boat Traveled 11.4 knots for 1 hour and 25 min , how far did it travel ?
Distance = SxT
25/60 =0.41666 + 1 
11.4 x 1.41666 = 16.149
So around 16.2 miles

If a boat traveled 16.2 miles at 11.4 knots how long would it take ?
Time = D/S
16.2/11.4 = 1.421 then - 1 = .421 x 60 = 25.26 then plus the 1 hour back on = 1 hour 25.26 min
So around 1 hour and 25 min

So each one id slightly different because of decimals i took of cause they were to far back.
Pretty good system i just learn t this today!!</description>
		<content:encoded><![CDATA[<p>This formula is really good just need to know how it works , it troubled me for ages.<br />
so if you want to find the speed you traveled , a boat covers 16.2miles in 1 hour and 25 min.<br />
speed = D/T<br />
25/60 =0.41666 + ! = 1.41666<br />
16.2 / 1.41666 = 11.435<br />
So around 11.4 knots was the boats speed</p>
<p>So if a boat Traveled 11.4 knots for 1 hour and 25 min , how far did it travel ?<br />
Distance = SxT<br />
25/60 =0.41666 + 1<br />
11.4 x 1.41666 = 16.149<br />
So around 16.2 miles</p>
<p>If a boat traveled 16.2 miles at 11.4 knots how long would it take ?<br />
Time = D/S<br />
16.2/11.4 = 1.421 then - 1 = .421 x 60 = 25.26 then plus the 1 hour back on = 1 hour 25.26 min<br />
So around 1 hour and 25 min</p>
<p>So each one id slightly different because of decimals i took of cause they were to far back.<br />
Pretty good system i just learn t this today!!
</p>
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		<title>by: Abby</title>
		<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-7013</link>
		<pubDate>Fri, 29 Jan 2010 07:04:09 +0000</pubDate>
		<guid>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-7013</guid>
					<description>this helped!!!!!!!!!!11 thanx.....   So its:       
        Speed=Distance(DEVIDED by)Times
        Distance=Times(MULTIPLY by)Speed
        Times=Speed(DEVIDED BY)Distance</description>
		<content:encoded><![CDATA[<p>this helped!!!!!!!!!!11 thanx&#8230;..   So its:<br />
        Speed=Distance(DEVIDED by)Times<br />
        Distance=Times(MULTIPLY by)Speed<br />
        Times=Speed(DEVIDED BY)Distance
</p>
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		<title>by: James</title>
		<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-6220</link>
		<pubDate>Sun, 01 Nov 2009 20:57:58 +0000</pubDate>
		<guid>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-6220</guid>
					<description>Really good help, and some of the comment gave good advice as well! Thanks guys!</description>
		<content:encoded><![CDATA[<p>Really good help, and some of the comment gave good advice as well! Thanks guys!
</p>
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		<title>by: matty</title>
		<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-6092</link>
		<pubDate>Tue, 13 Oct 2009 19:57:46 +0000</pubDate>
		<guid>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-6092</guid>
					<description>do you always have to turn time into decimals and do yo do it by dividig the number by 60?</description>
		<content:encoded><![CDATA[<p>do you always have to turn time into decimals and do yo do it by dividig the number by 60?
</p>
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		<title>by: Deborah</title>
		<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-5976</link>
		<pubDate>Mon, 21 Sep 2009 17:02:13 +0000</pubDate>
		<guid>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-5976</guid>
					<description>This confuses me. Here's my question:
Janine walks at 6km/h for 1 hour 30 minutes then 4km/h for 2 hours 15 minutes. How far does she walk in total.?

Could you tell me how to work this out using the triangle please. =)</description>
		<content:encoded><![CDATA[<p>This confuses me. Here&#8217;s my question:<br />
Janine walks at 6km/h for 1 hour 30 minutes then 4km/h for 2 hours 15 minutes. How far does she walk in total.?</p>
<p>Could you tell me how to work this out using the triangle please. =)
</p>
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		<title>by: moises</title>
		<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-5711</link>
		<pubDate>Thu, 23 Jul 2009 17:16:43 +0000</pubDate>
		<guid>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-5711</guid>
					<description>hi

i have a problem that i want to throw out there
ok,  "if you have to walk 1250ft and the speed that you are walking is 
4 miles an hour

how long will it take to finish the 1250ft?"

i tried your formula and when i divided the speed, which is 4 mgh and the distance, which is 1250ft i got 312.5..

so is 312.5, minuits, hours or seconds???</description>
		<content:encoded><![CDATA[<p>hi</p>
<p>i have a problem that i want to throw out there<br />
ok,  &#8220;if you have to walk 1250ft and the speed that you are walking is<br />
4 miles an hour</p>
<p>how long will it take to finish the 1250ft?&#8221;</p>
<p>i tried your formula and when i divided the speed, which is 4 mgh and the distance, which is 1250ft i got 312.5..</p>
<p>so is 312.5, minuits, hours or seconds???
</p>
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		<title>by: Nahum</title>
		<link>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-5595</link>
		<pubDate>Wed, 08 Jul 2009 05:51:11 +0000</pubDate>
		<guid>http://gcsemaths.org.uk/2006/11/09/speed-distance-and-time/#comment-5595</guid>
					<description>Hi Ali, Molly, Martin, and anybody else who may be struggling - 

You should keep your units the same. Here's a quick example:

You travel 25 miles at 50MPH in ? time...
 - use HOURS as your unit, since it's miles per HOUR. Cover up the T in the triangle with your thumb - you're left with D÷S. So 25÷50 is 0.5. That's your time: 0.5 hours. 

If you want, times the decimal by 60 to find the minutes. If you are given time in HOURS and MINUTES, instead of decimals, DIVIDE the minutes by 60 to get a decimal of the hour. 

What I see some people struggling with is when conversion is brought into the picture too. Sometimes you may be presented with a question like "How long does it take to drive 35 miles at 80km/h". If you are doing a paper, or have instructions it will usually tell you what unit your answer will have to be in. If not, convert one of the two so they are the same. Your answer will probably be a confusing number with endless decimals. If not told, make an educated guess to round your number. Three D.P. is usually a good idea.

So remember:

 - Keep the units the same
 - Work in a decimal timescale until the end.</description>
		<content:encoded><![CDATA[<p>Hi Ali, Molly, Martin, and anybody else who may be struggling - </p>
<p>You should keep your units the same. Here&#8217;s a quick example:</p>
<p>You travel 25 miles at 50MPH in ? time&#8230;<br />
 - use HOURS as your unit, since it&#8217;s miles per HOUR. Cover up the T in the triangle with your thumb - you&#8217;re left with D÷S. So 25÷50 is 0.5. That&#8217;s your time: 0.5 hours. </p>
<p>If you want, times the decimal by 60 to find the minutes. If you are given time in HOURS and MINUTES, instead of decimals, DIVIDE the minutes by 60 to get a decimal of the hour. </p>
<p>What I see some people struggling with is when conversion is brought into the picture too. Sometimes you may be presented with a question like &#8220;How long does it take to drive 35 miles at 80km/h&#8221;. If you are doing a paper, or have instructions it will usually tell you what unit your answer will have to be in. If not, convert one of the two so they are the same. Your answer will probably be a confusing number with endless decimals. If not told, make an educated guess to round your number. Three D.P. is usually a good idea.</p>
<p>So remember:</p>
<p> - Keep the units the same<br />
 - Work in a decimal timescale until the end.
</p>
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